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Chicken soop
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![]() #1 passes to #4. #5 searches across the lane. #1 gets to the left block. |
![]() #2 replaces #1. #4 looks at #3 first, then passes back to #2. On the catch by #2, #1 cross screens for #5. #5 uses the screen. |
![]() #2 sees #5 in the post. #4 and #3 come together to form a staggered double screen for #1. #1 uses the screens and receives a pass from #2. |
Created with Basketball Playbook from Jes-Soft
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